(x+∛(1-x³))(x²-x∛(1-x³)+∛(1-x³)²)
lim (x+∛(1-x³) )=[∞-∞]= lim ------------------------------------------- =
x→∞ x→∞ (x²-x∛(1-x³)+∛(1-x³)²)
x³+1-x³ 1
lim ----------------------------------=lim ----------------------------------= 1/∞=0
x→∞ (x²-x∛(1-x³)+∛(1-x³)²) x→∞ (x²-x∛(1-x³)+∛(1-x³)²)