Помогите! срочно!!! спасибо!

$\sqrt{2} cos( \frac{2x}{3} + \frac{ \pi}{4})=1 \\ cos( \frac{2x}{3} + \frac{ \pi}{4})= \frac{1 }{ \sqrt{2} } = \frac{ \sqrt{2} }{2}$
$\frac{2x}{3} + \frac{ \pi}{4} = \frac{ \pi }{4};$ $\frac{2x}{3} =0$ x=0

$\frac{2sinx+ \sqrt{2} }{2cosx- \sqrt{2} } = 0;\left \{ {{2sinx+ \sqrt{2} =0} \atop {2cosx- \sqrt{2} \neq 0}} \right. = \left \{ {{sinx= - \frac{ \sqrt{2}}{2} } \atop {cosx\neq \frac{\sqrt{2} }{2} }} \right.$ $x= \frac{5 \pi }{4}$