Sin2(x+П\3)=1+cos2(x+П\3)

Question

Sin2(x+П\3)=1+cos2(x+П\3)

Answer 1

sin²(x+π/3)=1+cos²(x+π/3)

cos²(x+π/3)-sin²(x+π/3)=-1

cos(2x+2π/3)=-1

2x+2π/3=π+2πn , n∈Z

2x=π-2π/3+2πn

2x=π/3+2πn

x=π/6+πn , n∈Z