(3x+1)^2-(3x-1)2^=x+5

Question

(3x+1)^2-(3x-1)2^=x+5

Answer 1

(3х+1)^2-(3x-1)^2=x+5
(3x+1)^2=(3x+1)*(3x+1)=9x^2+2*3x*1+1^2=9x^2-6x+1
(3x-1)^2=(3x-1)*(3x-1)=9x^2-2*3x*1+1^2=9x^2-6x+1
9x^2+6x+1-9x^2+6x-1=x+5
6x+6x=x+5
12x=x+5
12x-x=5
11x=5
x=5/11