(2y-3)5y=10(y²-1) уравнение

Question

(2y-3)5y=10(y²-1) уравнение

Answer 1

5y(2y - 3) = 10(y^2 - 1)
10y^2 - 15y = 10y^2 - 10
10y^2 - 15y - 10y^2 + 10 = 0 
- 15y + 10 = 0 
- 15y = - 10
15y = 10
y = 10/15 = 2/3