sin^3(a-270°)cos(360°-a)/tg^3(a-90°)cos^3(a-270°)

Question

sin^3(a-270°)cos(360°-a)/tg^3(a-90°)cos^3(a-270°)

Answer 1

sin^3x/sin^3x*cos^2x/cos^3x= sin^3x*cos^3x/six^3x*cos^2x=cosx Вроде так ;)