Логорифм???????????????????????????????????????

$\log_213+2=\log_2(7x-4),$

ОДЗ: $7x-4\ \textgreater \ 0,\\7x\ \textgreater \ 4,\\x\ \textgreater \ \frac{4}{7}.$

$\log_213-\log_2(7x-4)=-2,\\\\\log_2{\left(\frac{13}{7x-4}\right)}=-2,\\\\\log_2{\left(\frac{13}{7x-4}\right)}=\log_2{\frac{1}{4}},\\\\\frac{13}{7x-4}=\frac{1}{4},\\\\\frac{13}{7x-4}-\frac{1}{4}=0,\\\\\frac{13\cdot4-(7x-4)}{4(7x-4)}=0,\\\\\frac{52-7x+4}{4(7x-4)}=0,\\\\56-7x=0,\\\\7x=56,$

$x=8$ — удовлетворяет ОДЗ.

Ответ: $x=8$ .