Sin(90°-Π/4)+cos+-11Π/6)+tg(Π/2+2Π/3)

Question

Sin(90°-Π/4)+cos+-11Π/6)+tg(Π/2+2Π/3)

Answer 1

Cosπ/4+cos(2π-π/6)+ctg2π/3=cosπ/4+cosπ/6+ctg(π-π/3)=
=cosπ/4+cosπ/6-ctgπ/3=√2/2+√3/2-√3/3=(3√2+3√3-2√3)/6=
=(3√2+√3)/6