Решите систему уравнений

Решите задачу:

$\left \{ {{ (\frac{1}{3})^{2x-y}= \frac{1}{ \sqrt{3} } } \atop { 5^{3x-y}= \sqrt[3]{5} } \right. \ \ \ \textless \ =\ \textgreater \ \ \ \left \{ {{ (\frac{1}{3})^{2x-y}= (\frac{1}{3 } )^{ \frac{1}{2}} } \atop { 5^{3x-y}= 5^{ \frac{1}{3}} } \right. \ \ \ \textless \ =\ \textgreater \ - \left \{ {{2x-y= \frac{1}{2}\} \atop {3x-y= \frac{1}{3}\}} \right. \\ \\ -x= \frac{1}{2} - \frac{1}{3} = \frac{1}{6} \\ \\ x=- \frac{1}{6} \\ \\ 2x-y= \frac{1}{2} \\ \\ y=2x- \frac{1}{2} =2 (-\frac{1}{6})- \frac{1}{2} =- \frac{1}{3} - \frac{1}{2}=- \frac{5}{6} \\ \\$
$OTBET: \ ( - \frac{1}{6} ;\ - \frac{5}{6} )$