3log3(4-x)>9 помогите решить
log3(4-x)>3
log3(4-x)>log327
4-x>27
x<-23 4-x>0 x<4</p>
ответ х<-23</p>
9\\log_3(4-x)>3\\log_3(4-x)>log_33^3\\4-x>27\\x<-23\\\boxed{\bf x\in(-\infty;-23)}" alt="3log_3(4-x)>9\\log_3(4-x)>3\\log_3(4-x)>log_33^3\\4-x>27\\x<-23\\\boxed{\bf x\in(-\infty;-23)}" align="absmiddle" class="latex-formula">