СОКРАТИТЕ ДРОБЬ: 2x^2+x-1 ________ 3x^2+4x+1

Question

СОКРАТИТЕ ДРОБЬ:
2x^2+x-1
________
3x^2+4x+1

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Answer 1

(2x²+x-1)/(3x²+4x+1)
2x²+x-1=0  D=9      x₁=-1    x₂=1/2
3x²+4x+1=0   D=4  x₁=-1    x₂=-1/3   ⇒
(x+1)(x-1/2)/((x+1)(x+1/3))=(x-1/2)/(x+1/3).