система
{2xy=5
2x+y=6
{2xy=5 => {y=6-2x => { y=6-2x => {y=6-2x
2x+y=6 => {2x(6-2x)=5 => {12x-4x^2-5=0 => {4x^2-12x+5=0 (1)
(1): 4x^2-12x+5=0
D=144-4*4*5=64
x1=(12-8)/8=1/2 => y1=6-2*1/2=5
x2=(12+8)/8=5/2 y2=6-2*5/2=1
Ответ: (0,5;5);(2,5;1)