7(3y-5)=10(3-2y) 14(3y-2)= -7(4-6y)

Question

7(3y-5)=10(3-2y) 14(3y-2)= -7(4-6y)

Answer 1

7(3у-5)=10(3-2у)
21у-35=30-20у
41у=65
у=1цел 24/41

14(3у-2)=-7(4-6у)
42у-28=-28+42у
0у=0
у=0