Log10(x-5)^2<2 Очень нужно!!

Решите задачу:

$log_{10}(x-5)^2\ \textless \ 2\\\\lg(x-5)^2\ \textless \ 2\; \; ;\; \; \; ODZ;\; (x-5)^2\ \textgreater \ 0\; \to \; x\ne 5\\\\(tak\; kak\; pri\; x=5\; \; :\; (x-5)^2=0\; ,\; a \; nyzno\; (x-5)^2\ \textgreater \ 0\; )\\\\lg(x-5)^2\ \textless \ lg10^2\\\\(x-5)^2\ \textless \ 10^2\\\\(x-5)^2-10^2\ \textless \ 0\; ;\; \qquad a^2-b^2=(a-b)(a+b)\\\\(x-5-10)(x-5+10)\ \textless \ 0\\\\(x-15)(x+5)\ \textless \ 0\\\\Znaki:\; \; \; +++(-5)---(15)+++\\\\x\in (-5;15)\\\\ \left \{ {{x\in (-5,15)} \atop {x\ne 5}} \right. \; \; \Rightarrow \; \; \; \; \underline {x\in (-5;5)\cup (5;15)}$