Помогите решит уравнения 1)sin2x=1,2)cos3x=0, 3)sin2x=0, 4)cos3x=1, 5)sin2x=1/2,...

Решите задачу:

$sin2x=1,2\\2x=(-1)^n arcsin \frac{6}{5}+ \pi n \\ x = (-1)^n \frac{1}{2}arcsin \frac{6}{5} + \frac{\pi n}{2}, \; n \in Z;\\\\ cos3x=0\\ 3x=\pm arccos0 + 2\pi n\\3x = \pm \frac{\pi}{2} + 2\pi n\\x= \pm \frac{\pi}{6}+ \frac{2\pi n}{3}, \; n\in Z;\\\\ sin2x=0\\2x=(-1)^n arcsin0 + \pi n, \\ 2x = \pi n, \\ x=\frac{\pi n}{2}, \; n\in Z;\\\\cos3x=1\\3x=\pm arccos1 +2\pi n\\3x=2\pi n\\ x= \frac{2\pi n}{3}, \; n\in Z; \\\\ sin2x=1,2\\2x=(-1)^n arcsin \frac{6}{5}+ \pi n \\ x = (-1)^n \frac{1}{2}arcsin \frac{6}{5} + \frac{\pi n}{2}, \; n \in Z;\\\\ cos3x=0\\ 3x=\pm arccos0 + 2\pi n\\3x = \pm \frac{\pi}{2} + 2\pi n\\x= \pm \frac{\pi}{6}+ \frac{2\pi n}{3}, \; n\in Z;\\\\ sin2x=0\\2x=(-1)^n arcsin0 + \pi n, \\ 2x = \pi n, \\ x=\frac{\pi n}{2}, \; n\in Z;\\\\cos3x=1\\3x=\pm arccos1 +2\pi n\\3x=2\pi n\\ x= \frac{2\pi n}{3}, \; n\in Z; \\\\ 3tg2(x+\frac{\pi}{4})=1\\tg2(x+\frac{\pi}{4})=\frac{1}{3}\\ 2(x+\frac{\pi}{4})=arctg \frac{1}{3}+\pi n\\ x+\frac{\pi}{4}=\frac{1}{2}arctg \frac{1}{3}+\pi n\\ x= \frac{1}{2}arctg \frac{1}{3}+\pi n -\frac{\pi}{4}, \; n \in Z.$