1.
a) √64/9 = 8/3 = 2'2/3 ; b) -3 ; c) 10"√(2^5)²= 10"√2^10 = 2
d) √[(11-√21)·(11+√21) = √[ 11² - (√21)²]= √(121 - 21) = 10
2
a) a³·√( 5²·2) = 5a³√2 b) a³b^4·√(49·3) = 7·√3·a³b^4
3
a^16 = (√72)² = 72 ; b^16 = 3^4 = 81 ⇒ a < b
4
A =[12·(∛6)²]/[∛6·(∛6)²] =(12·∛36)/6 = 2∛36
B =[6·∛3]/[∛(3²) ·∛3] = 6·∛3 /3 = 2∛3
C = [6·(3 - √3)]/[(3+√3)·(3-√3)] = 6·(3 - √3)/[3² -(√3)²] = 6·(3 - √3)/(9 - 6) = 2(3 - √3)