(3x-15)/x^2+5x-14>=0
(3x-15)/(x²+5x-14)≥0 x²+5x-14=0 D=81 x₁=2 x₂=-7 3(x-5)/((x-2)(x+7))≥0 |÷3 ОДЗ: x≠2 x≠-7 (x-5)/((x-2)(x+7)≥0 -∞_____-______-7______+______2_____-______5_____+_____+∞ x∈(-7;2)U[5;+∞).