1/x²+10x+25 - 1/x-5 = 10/25-x²
1/(x+5)*(x+5) - 1/x-5 = 10/-(x-5)(x-5) I (x+5)(x+5)(x-5)
1*(x+5)(x+5)(x-5)/(x+5)(x+5) - 1*(x+5)(x+5)(x-5)/x-5 = 10*(x-5)(x+5)(x+5)/-(x-5)(x-5)
x-5 - x²+25 = 10*x+5
x-5-(x+5)² = 10x+50
x-5-x²+25-10x=50
x-x²-10x=50-25
-x²-9x=25
-x(x+9)=25
-x=25 x+9=25
x=-25 x=25-9
x=16
5/x²+2x+1 - 1/x-1 = 2/1-x
5/(x+1)(x+1) - 1/x-1 = 2/-(x-1) I (x+1)(x+1)(x-1)
5*(x+1)(x+1)(x-1)/(x+1)(x+1) - (x+1)(x+1)(x-1)/x-1 = 2(x+1)(x+1)(x-1)/-(x-1)
5*(x-1) - (x+1)(x+1) = 2*x²-1
5x-5 - x²+2x+1 = 2x²-2
5x-x²+2x-2x²=-2+5-1
-3x²+7x=2
-x(3x-7)=2
-x=2 3x-7=2
x=-2 3x=2+7
3x=9
x=3