(\frac{225}{144})^x;\\\\(\frac{12}{15})^{5x+1}>(\frac{12}{15})^{-2x};\\\\(0<\frac{12}{15}<1);\\\\5x+1<-2x;5x+2x<-1;7x<-1;\\\\x<-\frac{1}{7}" alt="(\frac{12}{15})^{5x+1}>(\frac{225}{144})^x;\\\\(\frac{12}{15})^{5x+1}>(\frac{12}{15})^{-2x};\\\\(0<\frac{12}{15}<1);\\\\5x+1<-2x;5x+2x<-1;7x<-1;\\\\x<-\frac{1}{7}" align="absmiddle" class="latex-formula">
ответ: x є 