3p+q/p^2-pq-3q+p/pq-q^2=

Question

3p+q/p^2-pq-3q+p/pq-q^2=

Answer 1

=(3p +q) /p(p -q) -(3q +p) /q(p -q) =

=(q(3p +q) -p(3q +p)) /pq(p -q) =(3pq +q² -3pq -p²) /pq(p -q) =

=(q² -p²) /pq(p -q) =

= -(p -q)(p +q) /pq(p -q) =

= -(p+q)/pq