f(x)'=(1/3*x^3-1/2*x^2-2x+3)' = x^2 - x -2 =0
квадратное уравнение
x^2 - x -2 =0
D = (-1)^2 - 4*1* -2 = 9
x = 1/2 (1 +/- 3)
x1 = -1 ; y1 = 1/3*(-1)^3-1/2*(-1)^2-2*(-1)+3 = 4_1/6
x2 = 2 ; y2 = 1/3*2^3-1/2*2^2-2*2+3 = -1/3
ОТВЕТ (-1 ; 4_1/6) ; (2; -1/3)