Y=log0.3 x+log0.3(9x^2-25) найдите область определения функции

Y=log₀,₃x+log₀,₃(9x²-25)

$\left \{ {{x\ \textgreater \ 0} \atop {9 x^{2} -25\ \textgreater \ 0}} \right. , \left \{ {{x\ \textgreater \ 0} \atop {(3x-5)*(3x+5)\ \textgreater \ )}} \right.$

1. (3x-5)*(3x+5)=0. x₁=5/3, x₂=-5/3
2. + - +
-------(-5/3)----------(5/3)-------------->x
3. x∈(-∞;-5/3)∪(5/3;∞)
\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \
----------(-5/3)---------(1)---------(5/3)------------>x
/ / / / / / / / / / / / / / / / / /
ответ: x∈(5/3;∞)