Помогите решить систему
{х+у=3(х-у) {х^2+у^2=90 {х+у=3х-3у {х^2+у^2=90 {х+у-3х+3у=0 {х^2+у^2=90 {-2х+4у=0 {х^2+у^2=90 {х-2у=0 {х^2+у^2=90 х=2у 4у^2+у^2=90 5у^2=90 у^2=18 у1=-V18=-3V2 y2=3V2 x1=-6V2 x2=6V2 (-6V2;-3V2)(6V2;3V2)