293(3,4) выполните действия

3) $12 \frac{13}{48}-(9 \frac{17}{32}-4 \frac{5}{24})=12 \frac{26}{96}-9 \frac{51}{96}+4 \frac{20}{96}=16 \frac{46}{96}-9 \frac{51}{96}=15 \frac{142}{96}-9 \frac{51}{96}=6 \frac{91}{96}$
4) $(18 -10\frac{18}{35})-(3 \frac{9}{28}+2 \frac{3}{20})=(17 \frac{35}{35} -10\frac{18}{35})-(3 \frac{45}{140}+2 \frac{21}{140})=7 \frac{25}{35}- 5 \frac{66}{140}=7 \frac{50}{70}- 5 \frac{33}{70}=2\frac{17}{70}$