Решите уравнение cos2x=-1/2
cos2x=-1/2
2х = ±2П/3 + 2Пn, nєZ
х = ±2П/6 + 2Пn/2, nєZ
х = ±П/3 + Пn, nєZ
2x = ±2pi/3 +2pik /:2
x = ±pi/3 +pik, k∈Z