Помогите решить номер 1, пожалуйста!

Решите задачу:

$\frac{16^{n+1}+2^{n+4}}{15\cdot 2^{n}(8^{n}+1)} = \frac{(2^4)^{n+1}+2^{n}\cdot 2^4}{15\cdot 2^{n}\cdot ((2^3)^{n}+1)} = \frac{2^{4n}\cdot 2^4+2^{n}\cdot 2^4}{15\cdot 2^{n}(2^{3n}+1)} =$

$= \frac{2^{n}\cdot 2^4(2^{3n}+1)}{15\cdot 2^{n}(2^{3n}+1)} = \frac{2^4}{15} = \frac{16}{15} \\\\\\ \frac{6^{n+2}+6^{n+1}-6^{n}}{6^{n+2}-6^{n}} = \frac{6^{n+2}-6^{n}}{6^{n+2}-6^{n}} + \frac{6^{n+1}}{6^{n+2}-6^{n}} =1+ \frac{6^{n}\cdot 6}{6^{n}(6^2-1)} =\\\\=1+ \frac{6}{36-1} =1+ \frac{6}{35}=1 \frac{6}{35}$