Помогите с алгеброй, пожалуйста!

$(m-3)^2: \frac{m^2-9}{6} = (m-3)^2* \frac{6}{m^2-9} = \frac{6*(m-3)^2}{m^2-3^2} = \frac{6*(m-3)*(m-3)}{(m-3)*(m+3)} =$

$=\frac{6(m-3)}{m+3}$
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$\frac{x}{3(x-2)}*( \frac{x}{2}- \frac{2}{x})= \frac{x}{3(x-2)}*( \frac{x*x}{2*x}- \frac{2*2}{x*2})= \frac{x}{3(x-2)}*( \frac{x^2}{2x}- \frac{2^2}{2x})=$

$= \frac{x}{3(x-2)}*( \frac{x^2-2^2}{2x}) = \frac{x*(x^2-2^2)}{3(x-2)*2x} = \frac{x*(x-2)*(x+2)}{x*(x-2)*6} = \frac{x+2}{6}$
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$(4a^4b^3) \frac{(2a^3b)^3}{(a+b)}=(4a^4b^3) \frac{(2^1a^3b^1)^3}{(a+b)}=(4a^4b^3) \frac{2^{1*3}a^{3*3}b^{1*3}}{(a+b)}=$

$=(4a^4b^3) \frac{2^{3}a^{9}b^{3}}{(a+b)}=\frac{4a^4b^3*2^{3}a^{9}b^{3}}{a+b}=\frac{4*2^3*a^4*a^9*b^3*b^3}{a+b}=\frac{4*8*a^{4+9}*b^{3+3}}{a+b}=$

$=\frac{32*a^{13}*b^{6}}{a+b} =\frac{32a^{13}b^{6}}{a+b}$