Arccos (3x-3.5)=2pi/3

Question

Arccos (3x-3.5)=2pi/3

Answer 1

Arccos(3x - 3,5) = 2П\3
3х - 3,5 = cos(2П\3)
3х - 3,5 = -1\2 | +3,5
3х = 3
х = 1