Докажите тождество3n-7(n-2)+3(4-2n)=26-10n

Question

Докажите тождество3n-7(n-2)+3(4-2n)=26-10n

Answer 1

3n-7(n-2)+3(4-2n)=26-10n
3n-7n+14+12-6n=26-10n
-10n+26=26-10n
26-10n=26-10n
Тождество доказано!!!!!

Answer 2

3n-7(n-2)+3(4-2n)=3n-7n+14+12-6n=26-10n