Метод Крамера. Пожалуйста помогите!!!

$d = \left[\begin{array}{ccc}2&-1&1\\3&2&2\\1&-2&1\end{array}\right] = 4-2-6-2+3+8=5 \\ \\ dx = \left[\begin{array}{ccc}2&-1&1\\-2&2&2\\1&-2&1\end{array}\right] = 4-2+4-2-2+8=10 \\ \\ dy = \left[\begin{array}{ccc}2&2&1\\3&-2&2\\1&1&1\end{array}\right] = -4+4+3+2-6-4=-5 \\ \\ dz = \left[\begin{array}{ccc}2&-1&2\\3&2&-2\\1&-2&1\end{array}\right] =4+2-12-4+3-8= -15 \\ \\ x = \frac{dx}{d}= \frac{10}{5}=2; y = \frac{dy}{d}= \frac{-5}{5}=-1;z= = \frac{dz}{d}= \frac{-15}{5}=-3$
Ответ: (2; -1; -3)