Методом подстановки. x2-3y=1 x-2y=1 Помогите пж
X2-3y=1 x=1+2y (1+2y)2-3y=1 1+4y+4y2-3y-1=0 4y2+y=0 y(4y+1)=0 y=0 y=-1/4 x=1 x=1/2
Х^2-3y=1 x=1+2y (1+2y)^2-3y=1 x=1+2y 1+4y+4y^2-3y=1 x=1+2y 4y^2+y=0 x=1+2y y(4y+1)=0 x=1+2y y1=0 4y+1=0 x=1+2y y1=0 4y=-1 x=1+2y y1=0 y2= -(1/4) x1=1+2*0 x2=1+2*(-1/4) y1=0 y2= -(1/4) x1=1 x2=1-1/2 y1=0 y2= -(1/4) x1=1 x2=1/2=0,5