Доведи 3(a+1)+a<4(2+a); (7p-1)(7p+1)>4d(d+2)

Question

Доведи
3(a+1)+a<4(2+a);<br> (7p-1)(7p+1)>4d(d+2)

Answer 1

3(a+1)+a<4(2+a)<br>3a+3+a<8+4a<br>4a+4<8+4a<br>4a-4a<8-4<br>0<4<br>
(7p-1)(7p+1)>4d(d+2)
49p^2-1>4d^2+8d
49p^2-4d^2-8d>1