Решите уровнение6/1-2х+9/2х+1=12х^2-15/4х^2-1

Решите задачу:

$\frac{6}{1-2x} + \frac{9}{2x+1} = \frac{12x^{2}-15}{4x^{2}-1}$
$\frac{9}{2x+1} - \frac{6}{2x-1} - \frac{12x^{2}-15}{(2x-1)(2x+1)}=0$
$\left \{ {{9(2x-1)-6(2x+1)-(12x^{2}-15) = 0} \atop {2x-1 \neq 0; 2x+1 \neq 0}} \right.$
$\left \{ {18x-9-12x-6-12x^{2}+15 = 0} \atop {x \neq \pm \frac{1}{2}} \right.$
$\left \{ {-12x^{2}+6x = 0} \atop {x \neq \pm \frac{1}{2}} \right.$
$\left \{ {2x^{2}-x = 0} \atop {x \neq \pm \frac{1}{2}} \right.$
$\left \{ {x(2x-1) = 0} \atop {x \neq \pm \frac{1}{2}} \right.$
$\left \{ {x = 0; x = \frac{1}{2}} \atop {x \neq \pm \frac{1}{2}} \right.$
$x = 0$