Второе и третие задание
2 3 (1-2x)(1-3x)=(6x-1)x-1 1-3x-2x+6x²-6x²+x+1=0 4x=2 x=0,5
Решение во вложении.
![b)(a^3+3b)(a^2-3b)-(a^2+3b)(a^3-2b)[tex]=a^5+3a^2b-3a^3b-9b^2-a^5+2a^2b-3a^3b+6b^2=5a^2b-6a^3b-3b^2](https://tex.z-dn.net/?f=b%29%28a%5E3%2B3b%29%28a%5E2-3b%29-%28a%5E2%2B3b%29%28a%5E3-2b%29%5Btex%5D%3Da%5E5%2B3a%5E2b-3a%5E3b-9b%5E2-a%5E5%2B2a%5E2b-3a%5E3b%2B6b%5E2%3D5a%5E2b-6a%5E3b-3b%5E2 "b)(a^3+3b)(a^2-3b)-(a^2+3b)(a^3-2b)[tex]=a^5+3a^2b-3a^3b-9b^2-a^5+2a^2b-3a^3b+6b^2=5a^2b-6a^3b-3b^2")