Помогите решить уравнения срочно,заранее спасибо

Решите задачу:

$7x^2 - 34x - 5 = 0 (x - 5)(7x + 1) = 0 x1 = 5; x2 = -1/7$

$5y^2+3y = 0 y(5y + 3) = 0 y1 = 0; y2 = -3/5$

$x^2 - 11x - 26 = 0 (x - 13)(x + 2) = 0 x1 = 13; x2 = -2$

$6y^2 + 5y + 1 = 0 (2y + 1)(3y + 1) = 0 x1 = -1/2; x2 = -1/3$

$4x^2 - 64 = 0 4(x - 4)(x + 4) = 0 (x - 4)(x + 4) = 0 x1 = 4; x2 = -4$

$\frac{7c^2+13c-2}{c-7c^2} = 0$
$7c^2+13c - 2 = 0$
$(c+2)(7c-1) = 0$
$c = -2$

$\frac{7y^2-y}{2-13y-7y} = 0$
$7y^2-y = 0$
$y(7y - 1) = 0$
$y1 = 0; y2 = 1/7$