Помогите решить задание 2,(3)-1,(6) ------------------ х=2,(2) 0,1(3)+0,1(6)

$2.(3)=2+\frac{0.3}{1-0.1}=2+\frac{0.3}{0.9}=2+\frac{1}{3}=\frac{7}{3}$

$1.6=1+\frac{0.6}{1-0.1}=1+\frac{0.6}{0.9}=1+\frac{2}{3}=\frac{5}{3}$

$0.1(3)=0.1+\frac{0.03}{1-0.1}=\frac{1}{10}+\frac{0.03}{0.9}=\frac{1}{10}+\frac{1}{30}=\frac{4}{30}$

$0.1(6)=0.1+\frac{0.06}{1-0.1}=\frac{1}{10}+\frac{0.06}{0.9}=\frac{1}{10}+\frac{2}{30}=\frac{5}{30}$

$2.(2)=\frac{2}{1-0.1}=\frac{2}{0.9}=\frac{20}{9}$

$\frac{2.(3)-1.(6)}{0.1(3)+0.1(6)}=\frac{\frac{7}{3}-\frac{5}{3}}{\frac{4}{30}+\frac{5}{30}}=\frac{\frac{2}{3}}{\frac{9}{30}}=\frac{2*30}{3*9}=\frac{20}{9}$

$\frac{20}{9}x=\frac{20}{9}$

$x=1$