\ x_{1}=1, \ x_{2}=\frac{c}{a}\\ 2+(-1)+(-1)=0\\ x_{1}=1, \ x_{2}=\frac{-1}{2}=-\frac{1}{2}\\ 2x^{2}-x-1=2(x-1)(x+\frac{1}{2})\\\\ " alt="\frac{(-x^{2}-3x-2)}{x^{2}+4x+4}-\frac{2x^{2}-x-1}{x-1}\\\\ 1. \ -x^{2}-3x-2=0\\ D = b^{2}-4ac=(-3)^{2}-4\cdot (-1)\cdot (-2)=9-8=1\\ x_{1,2}=\frac{-b+/-\sqrt{D}}{2a}\\ x_{1}=\frac{3+1}{2\cdot (-1)}=\frac{4}{-2}=-2\\ x_{2}=\frac{3-1}{2\cdot (-1)}=\frac{2}{-2}=-1\\ -x^{2}-3x-2=-(x+1)(x+2)\\\\ 2. \ x^{2}+4x+4= (x+2)^{2}\\\\ 3. \ 2x^{2}-x-1=0\\ a+b+c = 0 \ => \ x_{1}=1, \ x_{2}=\frac{c}{a}\\ 2+(-1)+(-1)=0\\ x_{1}=1, \ x_{2}=\frac{-1}{2}=-\frac{1}{2}\\ 2x^{2}-x-1=2(x-1)(x+\frac{1}{2})\\\\ " align="absmiddle" class="latex-formula">