1.13 помогите решать

Question

1.13 помогите решать

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Answer 1

MHCl=69.5·0.0515·1.025=3.65g
nHCl=3.65/36.5=0.1mol
nCaC2=19.2/64=0.3mol
CaC2+HOH=Ca(OH)2+C2H2↑
1mol              1mol
nCaC2=nCa(OH)2=0.3mol
n²HCL=nCa(OH)2-nHCl=0.3-0.1=0.2mol
m²HCl=0.2·36.5=7.3g
mr-raHCL=7.3·100%/15.5%=47g
Vr-raHCL=m/ρ=47g/1.09g/ml=43ml