Решите пожалуйста неравенство!)
ОДЗ 5^x≠1⇒x≠0 U 5^x≠3⇒x≠log(5)3 5^x=a 2/(a-1) +(a-2)/(a-3)≥2 2-2/(a-1)-(a-2)/(a-3)≤0 (2a²-8a+6-2a+6-a²+2a+a-2)/(a-1)(a-3)≤0 (a²-7a+10)/(a-1)(a-3)≤0 a²-7a+10=0 a1+a2=7 U a1*a2=10⇒a1=2 U a2=5 a-1=0⇒a=1 a-3=0⇒a=3 + _ + _ + ------------(1)-----------------[2]-------------(3)---------------[5]---------------- 13Ответ x∈(0;log(5)2] U (log(5)3;1]
