4x*2 +6x -2= (x-1)*2
*2-квадрат
4x^2 +6x-2=(x-1)^2 4x^2+6x-2=x^2-2x+1 3x^2+8x-3=0 D1=16+9=25 x1=(-4+5)/3=1/3 x2=(-4-5)/3=-3 Ответ: -3; 1/3
4x^{2} + 6x - 2 = (x-1)^{2} 4x^{2} + 6x - 2 = x^{2} - 2x +1 4x^{2} + 6x - 2 - x^{2} +2x - 1 = 0 3x^{2} +8x - 3 = 0 D = 8^{2} - 4*3*(-3) = 64 - (-36) = 100 x_{1,2} = \frac{-8 \frac{+}{-} 10}{2*3} x_{1} = -3 x_{2} = \frac{1}{3}