2x-1/3-x+2/6=2(2x-1)-x-2/6=(4x-2-x-2)/6=(3x-4)/6 (3)
(3x+2)/5x-(5x+3y)/10xy-(y-1)/2y=[2y(3x+2)-5x-3y-5x(y-1)]/10xy=(x+1)/10x (2)
3)4a/(3a-6)+3a/(8-4a)=4a/3(a-2)+3a/4(2-a)=(16a-9a)/12(a-2)=7a/12(a-2) (4)
4)3a-12a²/(4a-1)=(12a²-3a-12a²)/(4a-1)=-3a/(4a-1)=3a/(1-4a) (3)