(3 7/12 - 2 13/24) * 4/5 + (4 1/18 - 3 7/12) * 6/17

$(3\frac{7}{12}-2\frac{13}{24})\cdot\frac{4}{5}+(4\frac{1}{18}-3\frac{7}{12})\cdot\frac{6}{17}=1$

1) $3\frac{7}{12}-2\frac{13}{24}=\frac{43}{12}-\frac{61}{24}=\frac{86-61}{24}=\frac{25}{24}=1\frac{1}{24}$

2) $4\frac{1}{18}-3\frac{7}{12}=\frac{73}{18}-\frac{43}{12}=\frac{146-129}{36}=\frac{17}{36}$

3) $1\frac{1}{24}\cdot\frac{4}{5}=\frac{25}{24}\cdot\frac{4}{5}=\frac{5}{6}$

4) $\frac{17}{36}\cdot\frac{6}{17}=\frac{1}{6}$

5) $\frac{5}{6}+\frac{1}{6}=\frac{5+1}{6}=\frac{6}{6}=1$