Помогите решить 2 и 3 номер

Решите задачу:

$2. \\ z1 = 5-6i; z2 = -2+3i \\ \\ z1 + z2 = 5 - 6i -2 + 3i = 3-3i \\ \\ z1 - z2 = 5 - 6i + 2 - 3i = 7 - 9i \\ \\ z1 * z2 = (5-6i)*(-2+3i) = -10+15i+12i-18*(-1)=8+27i \\ \\ \frac{z1}{z2} = \frac{5-6i}{-2+3i} = \frac{(5-6i)*(-2-3i)}{(-2+3i)*(-2-3i)} = \frac{-10-15i+12i-18}{13} = \frac{-28-3i}{13} = \frac{-28}{13}+\frac{-3i}{13} \\ \\ \\ 3.\\ x^2-10x+34 = 0 \\ D = 100 - 136 = -6 = (\sqrt{6i})^2 \\ \\ x_1=\frac{10+6i}{2} = 5 + 3i ; \ \ \ x_2 = \frac{10-6i}{2} = 5 - 3i \\ \\ \\ x^2-16x+65 = 0 \\ D = 256 - 260 = -4 = (\sqrt{2i})^2 \\ \\ x_1=\frac{16+2i}{2} = 8 + i ; \ \ \ x_2 = \frac{16-2i}{2} = 8 - i$