1)(x+5)(x-4)+x^2+18=02)(x+4)^2+x^2=2x-1

Question

1)(x+5)(x-4)+x^2+18=0
2)(x+4)^2+x^2=2x-1

Answer 1

1)(x+5)(x-4)+x^2+18=0
x^2+ x  - 20 + x^2 + 18 = 0
x^2 + x - 2 = 0
D = 1 + 8 = 9
x1=(-1+3)/2 = 1
x2 = (-1-3)/2 = -2
Ответ: -2;1

2)(x+4)^2+x^2=2x-1
x^2 + 8x + 16 + x^2 - 2x + 1 = 0
2x^2 + 6x+17 = 0
D1 = 9 -34 <0 Уравнение не имеет корней<br>