5.....__________________

Решите задачу:

$\left \{ {{ \frac{x^2}{y-1}=2 } \atop { \frac{x-1}{y+1} = \frac{1}{4} }} \right. \\ \left \{ {{ \frac{x^2}{y-1}=2 } \atop { 4x-4=y+1}} \right. \\ \frac{x^2}{4x-6}=2 } \\ \frac{x^2-8x+12}{4x-6}=0 \\ x^2-8x+12=0 \\ D=64-4*12=16 \\ \left \{ {{ x_{1} = \frac{8+4}{2}=6 } \atop { y_{1} = 24-5=19}} \right. \\ \left \{ {{ x_{2} = \frac{8-4}{2}=2 } \atop { y_{1} = 8-5=3}} \right. \\ Otvet: \frac{6}{19}; \frac{2}{3}.$