17(3c+5d)+6c-28d c+d=2

Question

17(3c+5d)+6c-28d c+d=2

Answer 1

17(3с+5d)+6c-28dc+d= 51c+85d+6c-28dc+d=57c+86d-28cd

Answer 2

51c+85d+6c-28d=57d+57c=57(d+c)
57*2=114