(3x-1)(2x+7)-(x+1)(6x-5)=16

Question

(3x-1)(2x+7)-(x+1)(6x-5)=16

Answer 1

Решение
6x^2 + 21х - 2х -7 - (6х^2-5x+6x-5)=16
6x^2+19x-7-6x^2 + 5x- 6x +5 =16
18х=18
x= 1

Answer 2

(3x-1)(2x+7)-(x+1)(6x-5)=16

6x²+19x-7-6x²-x+5=16

18x=18

x=1