(x-5)^2=0 (2x+1)^2+3=0 (3x-5)^2=0 3(x+4)^2=0

Question

(x-5)^2=0 (2x+1)^2+3=0 (3x-5)^2=0 3(x+4)^2=0

Answer 1

1) (x-5)²=0
x=5

2) (2x+1)²+3=0
4x²+4x+4=0
D<0 корней нет<br>
3) (3x-5)²=0
x=5/3

4) 3(x+4)²=0
x=-4