0}} \right." alt="\left \{ {{12log_3(x-5)\geq0} \atop {x-5>0}} \right." align="absmiddle" class="latex-formula">
5}} \right." alt="\left \{ {{log_3(x-5)\geq0} \atop {x>5}} \right." align="absmiddle" class="latex-formula">
5}} \right." alt="\left \{ {{x-5\geq1} \atop {x>5}} \right." align="absmiddle" class="latex-formula">
5}} \right." alt="\left \{ {{x\geq6} \atop {x>5}} \right." align="absmiddle" class="latex-formula">
Ответ:[6;+бескон.)