ПОМОГИТЕ СРОЧНО ПОЖАЛУЙСТА

$x^{ \sqrt[3]{ x^{2} } } =( \sqrt{x} ) ^{x}$
ОДЗ:
$\left \{ {{x \geq 0} \atop {x \neq 0}} \right., =\ \textgreater \ x\ \textgreater \ 0$
$x^{ \sqrt[3]{ x^{2} } } = (x^{ \frac{1}{2} } ) ^{x}$
$x^{ \sqrt[3]{ x^{2} } } = x^{ \frac{1}{2}*x }$
$\sqrt[3]{ x^{2} } = \frac{1}{2}*x$
$( \sqrt[3]{ x^{2} } ) ^{3} =( \frac{x}{2} ) ^{3}$
$x^{2} = \frac{ x^{3} }{8}$
$\frac{8 x^{2} - x^{3} }{ x^{3} } =0$
$\left \{ {{8 x^{2} - x^{3} =0} \atop { x^{3} \neq 0}} \right. , \left \{ {{ x^{2} *(8-x)=0} \atop {x \neq 0}} \right. =\ \textgreater \ x=8$